Same quantity of electricity is being used to liberate iodine (at anode) and a metal x (at cathode). The mass of x deposited is 0.617 g and the iodine is completely reduced by 46.3 cc of 0.124 M sodium thiosulphate. Find the equivalent mass of x.

108.2

Number of equivalent of \(I_2\) reduced

\(= 46.3 × 10^{−3} × 0.124\)

\(= 5.7 × 10^{−3}\)

Number of equivalent of \(I_2\) =  Number of equivalent of metal

\(5.7 × 10^{−3} = \frac{0.617}{E}\)

\(E = \frac{0.617}{5.7 × 10^{−3}}\)

\(E = 108.2\)