Let V and A denote the volume and surface area of a cuboid of dimension a, b and c units respectively. Which one is correct answer?

$\frac{A}{V}=\left(\frac{2}{a}+\frac{2}{b}+\frac{2}{c}\right)$

We have,

Dimensions of a cuboid = a, b and c units

Then the volume = a × b × c = V

and total surface area of cuboid = 2(ab + bc  + ca) = A

So, if we divide area by volume we get = \(\frac{A}{V}\) = \(\frac{2(ab + bc  + ca)}{a × b × c}\)

= $\frac{A}{V}=\left(\frac{2}{a}+\frac{2}{b}+\frac{2}{c}\right)$