Practicing Success
If $2 \cos ^2 \theta-1=0$, then find the value of $2 \sin ^2 \theta+\sin 2 \theta$. |
0 3 1 2 |
2 |
2cos²θ - 1 = 0 2cos²θ = 1 cos²θ = \(\frac{1}{2}\) cosθ = \(\frac{1}{√2}\) = cos 45º θ = 45º Now, 2sin²θ + sin2θ = 2sin²45º + sin90º = 2 × \(\frac{1}{2}\) + 1 = 1 + 1 = 2 The correct answer is Option (4) → 2 |