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CUET
-- Applied Mathematics - Section B2
Linear Programming
The minimum value of the objective function $Z= 30x + 10 y $ subject to the constraints $x+2y≤30, 3x+y ≥30, 4x+3y≥60, x, y ≥ 0$ is
100
450
300
1200
The correct answer is Option (3) → 300
$Z_{min}(10,0)=30×10+10×0$
$=300$
