If a-\(\frac{12}{a}\)=1, then find the

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If a-\(\frac{12}{a}\)=1,

then find the value of a²+\(\frac{16}{{a}^{2}}\)

Options:

Correct Answer:

Explanation:

Put a = 4 in equation.

4-\(\frac{12}{4}\)=1 (satisfying)

So, a²+\(\frac{16}{{a}^{2}}\) = (4)²+\(\frac{16}{({4})^{2}}\)

a²+\(\frac{16}{{a}^{2}}\) = 17