If a-\(\frac{12}{a}\)=1,
then find the value of a2+\(\frac{16}{{a}^{2}}\)
Answer & explanation
Correct answer: option 2
Put a = 4 in equation.
4-\(\frac{12}{4}\)=1 (satisfying)
So, a2+\(\frac{16}{{a}^{2}}\) = (4)2+\(\frac{16}{({4})^{2}}\)
a2+\(\frac{16}{{a}^{2}}\) = 17