CUET Preparation Today
If a-\(\frac{12}{a}\)=1, then find the value of a2+\(\frac{16}{{a}^{2}}\) |
15 17 11 19 |
17 |
Put a = 4 in equation. 4-\(\frac{12}{4}\)=1 (satisfying) So, a2+\(\frac{16}{{a}^{2}}\) = (4)2+\(\frac{16}{({4})^{2}}\) a2+\(\frac{16}{{a}^{2}}\) = 17 |
