Practicing Success
If for a differentiable function f, f(0) = f(1) = 0, f'(1) = 2 and $g(x) = f(e^x)e^{f(x)}$, then g'(0) is equal to |
1 2 0 none of these |
2 |
$g(x) = f(e^x)e^{f(x)}$ $∴g'(x) = f'(e^x).e^x.e^{f(x)}+f(e^x).e^{f(x)}.f'(x)$ Put x = 0 and f(0) = f(1) = 0, f'(1) = 2 $∴ g'(0) = 2 . 1 . 1 + 0 = 2$ |