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Home/Practice questions/General Aptitude Test
General Aptitude TestVerbal ReasoningOdd One Out/Classification

Choose the odd one9105, 9837, 7125, 4314, 3927, 2958

Choose the odd one

9105, 9837, 7125, 4314, 3927, 2958

Answer & explanation+

Correct answer: option 2

The correct answer is Option (2) → 9837

A number is divisible by 3 when the sum of its digits is divisible by 3, and by 9 when that sum is divisible by 9. All six numbers have digit sums divisible by 3; only one has a digit sum divisible by 9.

  • 9105: \(9+1+0+5=15\), divisible by 3, not by 9

  • 9837: \(9+8+3+7=27\), divisible by 9, so 9837 is the odd one out

  • 7125: \(7+1+2+5=15\), divisible by 3, not by 9

  • 4314: \(4+3+1+4=12\), divisible by 3, not by 9

  • 3927: \(3+9+2+7=21\), divisible by 3, not by 9

  • 2958: \(2+9+5+8=24\), divisible by 3, not by 9

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