CUET Preparation Today
Urn I contains 6 red balls and 4 black balls and Urn II contains 4 red balls and 6 black balls. One ball is drawn at random from Urn I and placed Urn II. If one ball is drawn at random from Urn II, then the probability that it is a red ball is : |
$\frac{3}{5}$ $\frac{4}{11}$ $\frac{23}{55}$ $\frac{2}{5}$ |
$\frac{23}{55}$ |
