Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The dimensions of $\frac{e^2}{2 \varepsilon_0(h c)}$ are

Options:

$\left(A^2 L^3 T^{4} M^{-4}\right)$

$\left(A^{-2} T^{-4} L^3 M\right)$

$\left(A^0 M^0 L^0 T^0\right)$

$\left(A T^{-2} L^{-1} M^{-1}\right)$

Correct Answer:

$\left(A^0 M^0 L^0 T^0\right)$

Explanation:

$\frac{\mathrm{C}^2}{\mathrm{C}^2 /\left(\mathrm{N} \times \mathrm{m}^2\right) \times \text { Joule } \times \text { sec } \times \text { meter } \times \mathrm{sec}^{-1}}$