The area of a right-angled triangle with hypotenuse 17 cm and one sid…

The correct answer is Option (2) → $60\, cm^2$

Given a right-angled triangle:

• Hypotenuse = 17 cm
• One side = 8 cm

First, find the other side using Pythagoras theorem:

$\text{Other side} = \sqrt{17^2 - 8^2} = \sqrt{289 - 64} = \sqrt{225} = 15 \text{ cm}$

Now calculate the area:

$\text{Area} = \frac{1}{2} \times 8 \times 15 = 60 \text{ cm}^2$