Let $f(x)=\left\{\begin{array}{l}|x-1|+a, x<1 \\ 2 x+3, x \geq 1\end{array}\right.$. If f (x) has a local minima at x = 1, then |
a ≥ 5 a > 5 a > 0 none of these |
a ≥ 5 |
Local minimum value of f(x) at x = 1, will be 5 i.e. 1 – x + a ≥ 5 at x = 1 ⇒ a ≥ 5 |