Solve the following: (a + b + c)(ab + bc + ca) - abc = ?

 (a + b + c)(ab + bc + ca) – abc = ?

Put a = b = c = 1

(1 + 1 + 1) (1 + 1 + 1) – 1

= 3 × 3 – 1 = 8

Now put their values  and satisfy from the options,

If we choose , (a + b)(b + c)(c + a)

= 2 × 2 × 2

8 (satisfied)

So the value of  (a + b + c)(ab + bc + ca) – abc = (a + b)(b + c)(c + a)