A closely wound circular coil of radius 10 cm carries a current of 6.4 A. If the number of turns in coil are 10 then magnetic moment of this coil is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $2.0096 A\, m^2$
Given,
R, Radius of coil = 10 cm = 0.1 m
I, Current in coil = 6.4 A
N, number of turns = 10
∴ Area of coil = $πr^2$
$=π×(0.1)^2$
$=0.0314m^2$
M, Magnetic moment = N.I.A
where,
N = Number of turns
I = Current flowing
A = Area of coil
$M=10×6.4×0.0314$
$=2.0096Am^2$