A closely wound circular coil of radius 10 cm carries a current of 6.4 A. If the number of turns in coil are 10 then magnetic moment of this coil is:

$2.0096 A\, m^2$

The correct answer is Option (1) → $2.0096 A\, m^2$

Given,

R, Radius of coil = 10 cm = 0.1 m

I, Current in coil = 6.4 A

N, number of turns = 10

∴ Area of coil = $πr^2$

$=π×(0.1)^2$

$=0.0314m^2$

M, Magnetic moment = N.I.A

where,

N = Number of turns

I = Current flowing

A = Area of coil

$M=10×6.4×0.0314$

$=2.0096Am^2$