In the given figure, AP bisects ∠BAC. If AB = 4 cm, AC = 6 cm and BP = 3 cm, then the length of CP is:
Answer & explanation
Correct answer: option 4
We are given that :-
AP bisects ∠BAC
⇒ \(\frac{AB}{AC}\) = \(\frac{BP}{CP}\)
\(\frac{4}{6}\) = \(\frac{3}{CP}\)
CP = 4.5 cm