The total cost of a firm is given by $C(x)=\frac{2x^3}{3}-4x^2+8x+7.$ The level of output at which marginal cost in minimum is : |
8 15 $\frac{2}{3}$ 12 |
$\frac{2}{3}$ |
The correct answer is Option (3) → $\frac{2}{3}$ The total cost is, $C(x)=2x^3-4x^2+8x+7$ $MC=\frac{d}{dx}C(x)=6x^2-8x+8$ for minimum, $MC'(c)=0$ $⇒12x-8=0$ $⇒x=\frac{2}{3}$ |