Which of the following transition metal ion is colourless?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(Sc^{3+}\)
A transition metal ion is coloured when an electron can be excited from a lower energy d orbital to a higher energy d orbital (a d–d transition) by absorbing visible light. This needs a partly filled d subshell. Sc (Z = 21) is [Ar]3d14s2; losing the two 4s electrons and the one 3d electron gives \( \ce{Sc^{3+}} \): [Ar]3d0. With no d electron there is no d–d transition, so Sc3+ is colourless.
Why the other options are incorrect
Option (2) V2+ — Incorrect. V (Z = 23) is [Ar]3d34s2; \( \ce{V^{2+}} \) is 3d3, partly filled, and its aqueous ion is violet.
Option (3) Mn2+ — Incorrect. Mn (Z = 25) is [Ar]3d54s2; \( \ce{Mn^{2+}} \) is 3d5, and its aqueous ion is pink.
Option (4) Co3+ — Incorrect. Co (Z = 27) is [Ar]3d74s2; \( \ce{Co^{3+}} \) is 3d6, a partly filled d subshell, so d–d transitions occur and its compounds are coloured.
NCERT (2026-27 edition):
Formation of Coloured Ions – Table 4.8: Colours of Some of the First Row (aquated) Transition Metal Ions
| Configuration | Example | Colour |
|---|---|---|
| 3d0 | Sc3+ | colourless |
| 3d0 | Ti4+ | colourless |
| 3d1 | Ti3+ | purple |
| 3d1 | V4+ | blue |
| 3d2 | V3+ | green |
| 3d3 | V2+ | violet |
| 3d3 | Cr3+ | violet |
| 3d4 | Mn3+ | violet |
| 3d4 | Cr2+ | blue |
| 3d5 | Mn2+ | pink |
| 3d5 | Fe3+ | yellow |
| 3d6 | Fe2+ | green |
| 3d6 | Co3+ | blue |
| 3d7 | Co2+ | pink |
| 3d8 | Ni2+ | green |
| 3d9 | Cu2+ | blue |
| 3d10 | Zn2+ | colourless |