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In the figure, what is the value of cot θ :
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$\frac{17}{18}$ $\frac{15}{17}$ $\frac{15}{8}$ $\frac{8}{15}$ |
$\frac{15}{8}$ |
By using pythagoras theorem , PR² = PQ² + QR² 17² = 8² + QR² QR² = PQ² + QR² = 289 - 64 = 225 QR = 15 Now, cotθ = \(\frac{B}{P}\) = \(\frac{15}{8}\)
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