Light from point source in air falls on a spherical glass surface (n=1.5 and radius of curvature= 10 cm). The distance of the light source from the glass surface is 50 cm. The position at which the image is formed is:

50 cm in the glass surface

The correct answer is Option (4) → 50 cm in the glass surface

Using lens-Maker formula,

$\frac{μ_2}{v}-\frac{μ_1}{u}=\frac{μ_2-μ_1}{R}$

and,

$μ_1=1$ (Air)

$μ_2=1.5$ (Glass)

$⇒\frac{1.5}{v}-\frac{1}{-50}=\frac{1.5-1}{10}$

$⇒v=50cm$