If $cot^2 θ + cot^4 θ = 2, $ then the value of $2sin^4θ + sin^2 θ $ is :
Answer & explanation
Correct answer: option 3
cot²θ + cot4 θ = 2
cot²θ ( 1 + cot²θ ) = 2
Using,
cosec²θ - cot²θ = 1
cot²θ ( cosec²θ ) = 2
\(\frac{cos²θ}{sin4 θ}\) = 2
cos²θ = 2sin4 θ
Now,
2sin4 θ + sin²θ
= cos²θ + sin²θ
= 1 { cos²θ + sin²θ = 1 }