CUET Preparation Today
If $cot^2 θ + cot^4 θ = 2, $ then the value of $2sin^4θ + sin^2 θ $ is : |
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cot²θ + cot4 θ = 2 cot²θ ( 1 + cot²θ ) = 2 Using, cosec²θ - cot²θ = 1 cot²θ ( cosec²θ ) = 2 \(\frac{cos²θ}{sin4 θ}\) = 2 cos²θ = 2sin4 θ Now, 2sin4 θ + sin²θ = cos²θ + sin²θ = 1 { cos²θ + sin²θ = 1 } |
