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What is the value of $ ( a+ b+ 2c) (a^2 + b^2 +4c^2 - ab - 2bc -2ca )$? |
$ a^3 - b^3 - c^3 - 6abc $ $ a^3 + b^3 + 4c^3 - 6abc $ $ a^3 - b^3 - 8c^3 - 3abc $ $ a^3 + b^3 + 8c^3 - 6abc $ |
$ a^3 + b^3 + 8c^3 - 6abc $ |
What is the value of $ ( a+ b+ 2c) (a^2 + b^2 +4c^2 - ab - 2bc -2ca )$ Put the value of a , b and c =1 and satisfy from the equation $ ( a+ b+ 2c) (a^2 + b^2 +4c^2 - ab - 2bc -2ca )$ = $ ( 1+ 1+ 2) (1 + 1 +4 ×1 - 1 - 2×1 -2×1 ) = 4 ( 6 - 5 ) = 4 If we take option 4 = $ a^3 + b^3 + 8c^3 - 6abc $ Put the values in this equation = $ 1 + 1 + 8 ×1 - 6 $ = 4 satisfied |
