An integrating factor of the differential equation
$y \log y \frac{d x}{d y}+x-\log y=0$, is
Answer & explanation
Correct answer: option 2
We have, $\frac{d x}{d y}+\frac{1}{y \log y} x=\frac{1}{y}$
Integrating factor = $e^{\int \frac{1}{y \log y}} d y=e^{\log (\log y)}=\log y$