The integrating factor of the differential equation $(x \log x) \frac{d y}{d x}+y=2 \log x$ is given by
Answer & explanation
Correct answer: option 3
We have,
$\frac{d y}{d x}+\frac{1}{x \log x} y=\frac{2}{x}$
∴ Integrating factor = $e^{\int \frac{1}{x \log x} d x}=e^{\log (\log x)}=\log x$