
Answer & explanation
Correct answer: option 4
$\text{Resolving Component of T }$
$ T cos\theta = mg $ ............(1)
$ T sin\theta = qE = q\frac{\sigma}{\epsilon_0}$ .............(2)
$\text{Dividing equation (1)( and (2),we get}$
$ tan\theta = \frac{q\sigma}{mg\epsilon_0}$
$\Rightarrow \sigma \propto tan\theta $