Practicing Success
Two coherent monochromatic light beams of intensities 16I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are - |
20I and I 36I and 4I 20I and 12I 36I and I |
36I and 4I |
$ I_{max} = (\sqrt{I_1}+ \sqrt{I_2})^2 = (\sqrt{16I}+ \sqrt{4I})^2 = 36I$ $ I_{min} = (\sqrt{I_1}- \sqrt{I_2})^2 = (\sqrt{16I}- \sqrt{4I})^2 = 4I$ |