Distance of a chord JK from the centre is 7 cm. If diameter of this circle is 50 cm, then what will be length of this chord?

48 cm

Diameter of circle = 50 cm

Radius = OJ = \(\frac{50}{2}\) = 25 cm

In triangle JOP,

OJ = Hypotenuse = 25

OP = Perpendicular = 7

Apply Pythagoras theorem

\( {OJ }^{2 } \) = \( {OP }^{2 } \) + \( {JP }^{2 } \)

\( {25 }^{2 } \) = \( {7 }^{2 } \) + \( {JP }^{2 } \)

\( {JP }^{2 } \) = 625 - 49

\( {JP }^{2 } \) = 576

JP = 24

Therefore, Length of chord JK = 2 x JP = 2 x 24 = 48 cm