Distance of a chord JK from the centre is 7 cm. If diameter of this circle is 50 cm, then what will be length of this chord?
Answer & explanation
Correct answer: option 3
Diameter of circle = 50 cm
Radius = OJ = \(\frac{50}{2}\) = 25 cm
In triangle JOP,
OJ = Hypotenuse = 25
OP = Perpendicular = 7
Apply Pythagoras theorem
\( {OJ }^{2 } \) = \( {OP }^{2 } \) + \( {JP }^{2 } \)
\( {25 }^{2 } \) = \( {7 }^{2 } \) + \( {JP }^{2 } \)
\( {JP }^{2 } \) = 625 - 49
\( {JP }^{2 } \) = 576
JP = 24
Therefore, Length of chord JK = 2 x JP = 2 x 24 = 48 cm