CUET Preparation Today
CUET
-- Mathematics - Section A
Applications of Derivatives
At what value of x is the function y = \( { x }^{ 2 } -4x\) attains its minimum value?
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$y=x^2-4x$
for critical points, $y'(x)=6$
$⇒2x-4=0$
$⇒x=2$
∴ At $x=2$ → minimum value
