At what angle the hour and minute hands of a clock are inclined at 15 min past 5?

$67\frac{1}{2}^{\circ}$

The correct answer is Option (4) → $67\frac{1}{2}^{\circ}$

TIME = 15 MIN PAST 5

ANGLE = (60 H -11MINUTE ) ÷ 2

           = (60 × 5 - 11 × 15) ÷ 2 

           = (300 - 165) ÷ 2 

           = 135 ÷ 2 

            = 67.5

         6712

6712∘
6712∘