Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius r/2 and lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is :
Answer & explanation
Correct answer: option 2
F = \(\frac{m (nv)^2}{r} \)
\(\frac{m (nv)^2}{r} = \frac{2 m v^2}{\frac{r}{2}}\)
n = 2