Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If the compound ratio of (Z : 16) and (81 : P) is 9 : 16, then what is the compound ratio of (P - Z) : 24 and 30 : (Z + P)?

Options:

\(\frac{3}{10}\)

1

\(\frac{10}{3}\)

\(\frac{1}{3}\)

Correct Answer:

1

Explanation:

The compound ratio of (Z : 16) and (81 : P) is 9 : 16

⇒ \(\frac{Z}{16}\) × \(\frac{81}{P}\) = \(\frac{9}{16}\)

\(\frac{Z}{P}\) = \(\frac{1}{9}\) ⇒ Z : P = 1 : 9

Compound ratio of (P - Z) : 24 and 30 : (Z + P) can be written as

⇒ \(\frac{P - Z}{24}\) × \(\frac{30}{Z + P}\) = \(\frac{9 - 1}{24}\) × \(\frac{30}{10}\) = 1