The reduction of cyclohexanone with $LiAlH_4$ will give: |
Cyclohexanol Cyclohexanaldehyde Benzoic acid Phenol |
Cyclohexanol |
The correct answer is Option (1) → Cyclohexanol $LiAlH_4$ is a strong reducing agent that reduces ketones to secondary alcohols. Option 1: Cyclohexanol Cyclohexanone is a ketone. $LiAlH_4$ donates hydride ($H^-$) to the carbonyl carbon, converting the C=O group into $-OH$. Thus, ketone → secondary alcohol Product formed is cyclohexanol. Option 2: Cyclohexanaldehyde Reduction does not convert ketones into aldehydes. Instead, aldehydes are formed by mild oxidation of primary alcohols. Option 3: Benzoic acid This is an oxidation product and unrelated to reduction of cyclohexanone. Option 4: Phenol Phenol formation would require aromatic ring formation, which does not occur in this reaction. |