The reduction of cyclohexanone with $LiAlH_4$ will give:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Cyclohexanol
$LiAlH_4$ is a strong reducing agent that reduces ketones to secondary alcohols.
Option 1: Cyclohexanol
Cyclohexanone is a ketone. $LiAlH_4$ donates hydride ($H^-$) to the carbonyl carbon, converting the C=O group into $-OH$.
Thus, ketone → secondary alcohol
Product formed is cyclohexanol.
Option 2: Cyclohexanaldehyde
Reduction does not convert ketones into aldehydes. Instead, aldehydes are formed by mild oxidation of primary alcohols.
Option 3: Benzoic acid
This is an oxidation product and unrelated to reduction of cyclohexanone.
Option 4: Phenol
Phenol formation would require aromatic ring formation, which does not occur in this reaction.