A game consists of tossing a coin 3 times. Hanif wins if all the tosses give the same result. What is the probability that he loses the game?
Answer & explanation
Correct answer: option 2
Total outcomes = HHH , HHT, HTH, HTT, THH, THT, TTH, TTT = 8
Hanif winning chances = HHH , TTT
Hanif loosing outcomes = HHT, HTH, HTT, THH, THT, TTH = 6
Probability that Hanif loses the game = \(\frac{6}{8}\)
= \(\frac{3}{4}\)
The correct answer is Option (2) → $\frac{3}{4}$