The height of a pole is 2√3 meters and the length of its shadow is 2…

Let AB be the pole and AC be its shadow, as shown in the above figure.

Let angle of elevation,ACB=θ

Then, AB=2√3m and

AC=2m

Tanθ = AB/AC =2√3/2 = √3

Since, tanθ = √3,

Θ = 60^o