What is the length of the longest pole that can fit itself in a hall 60 feet long, 30 feet broad and 20 feet high?
Answer & explanation
Correct answer: option 1
Length of diagonal of a cuboid = \(\sqrt {(l^2 + b^2 + h^2 ) }\)
Where,
l= length ,
b= breadth
h = height
Here, hall has length = 60 feet ,
breadth = 30 feet and
height = 20 feet
As, the length of the longest rod that can be placed in a room is it's diagonal
So, length of the longest rod = \(\sqrt {(60^2 + 30^2 + 20^2 ) }\)
= \(\sqrt {(4900 }\)) = 70 feet