If $a=22$ and $b=18,$ then the value of

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Home Questions F76UGDKT3E

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Simplification

Question:

If $a=22$ and $b=18,$ then the value of $\frac{a^2+b^2+ab}{a^3-b^3}$ is

Options:

$\frac{1}{2}$

$\frac{1}{4}$

Correct Answer:

$\frac{1}{4}$

Explanation:

$a=22$ and $b=18,$ then the value of $\frac{a^2+b^2+ab}{a^3-b^3}$

We can reform this equation as, $\frac{a^2+b^2+ab}{(a^2+b^2+ab)(a - b)}$

= $\frac{1}{(a - b)}$ = $\frac{1}{(22 - 18)}$ = $\frac{1}{4}$