If a=22 and b=18, then the value of (a^2+b^2+ab)/(a^3-b^3) is

$a=22$ and $b=18,$ then the value of $\frac{a^2+b^2+ab}{a^3-b^3}$

We can reform this equation as, $\frac{a^2+b^2+ab}{(a^2+b^2+ab)(a - b)}$

= $\frac{1}{(a - b)}$ = $\frac{1}{(22 - 18)}$  = $\frac{1}{4}$