A 10 V battery having 3 Ω internal resistance is connected with a 200 V battery and a 35 Ω resistance as shown in the figure. The terminal potential drop at 10 V battery will be:

25 V

The correct answer is Option (2) → 25 V

Since the batteries oppose each other:
Net emf = 200 − 10 = 190 V

External resistance = 35 Ω
Internal resistance = 3 Ω
Total = 35 + 3 = 38 Ω

Current = 190 / 38 = 5 A

Since it is being charged, terminal voltage = E + Ir

Terminal voltage = 10 + (5 × 3) = 10 + 15 = 25 V