Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The total energy of electron in the nth stationary orbit of hydrogen is : 

Options:

\(\frac{13.6}{n^{2}}\) Joule

\(\frac{13.6}{n^{2}}\) eV

- \(\frac{13.6}{n^{2}}\) Joule

- \(\frac{13.6}{n^{2}}\) eV

Correct Answer:

- \(\frac{13.6}{n^{2}}\) eV

Explanation:

The total energy of electron in the nth stationary orbit of hydrogen is = - \(\frac{13.6}{n^{2}}\) eV.