Using the given information, calculate the mass defect of ${}_8^{16}O$ nucleus in $MeV/c^2$.
mass of electron, $m_e = 0.00055 u$
mass of proton, $m_p= 1.00727 u$
mass of neutron, $m_n = 1.00866 u$
experimental mass of nucleus = 15.99053 u
$1 u=931.5\, MeV/c^2$ (where u= atomic mass unit)
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $127.5\, MeV/c^2$
Total mass of the nucleus = $Z×m_p+(A-Z)m_n$
$=8×1.007+8×1.008$
$=16.127U$
Experimental Mass (M) = 15.990 U
∴ Mass Deficit = Total mass - Experimental Mass
$=16.127-15.990=0.136U$
∴ Mass Deficit $\left(\frac{MeV}{C^2}\right)$ = 0.136 × 931.5
$≃127.5\frac{MeV}{C^2}$