The planes \(2x-y+4z=5\) and \(5x-2.5y+10z=6\) are
Answer & explanation
Correct answer: option 2
Planes are
$2x-y+4z=5$......(1)
$5x-2.5y+10z=6$......(2)
Multiply equation (2) by 2
$⇒10x-5y+20z=12$
Divide this equation by 5
$⇒2x-y+4z=\frac{12}{5}$
Now this equation parallel to (1)