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The planes \(2x-y+4z=5\) and \(5x-2.5y+10z=6\) are |
perpendicular parallel Intersect \(y-\) axis passes through |
parallel |
Planes are $2x-y+4z=5$......(1) $5x-2.5y+10z=6$......(2) Multiply equation (2) by 2 $⇒10x-5y+20z=12$ Divide this equation by 5 $⇒2x-y+4z=\frac{12}{5}$ Now this equation parallel to (1) |
