The Brewster's angle for air to water transition is (Refractive index of water $=\frac{4}{3}$)
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\tan ^{-1}\left(\frac{4}{3}\right)$
By Brewster’s law
$i_c=\tan ^{-1}(\mu)$
$i_c=\tan ^{-1}\left(\frac{4}{3}\right)$