If tanα + sinβ = m
cotα + cosecβ = n, α ≠ β, then
find the value of cosec2β (\(\frac{m}{n}\))2 + 4.
Answer & explanation
Correct answer: option 1
Put α = 45°, β = 30°
[∵ Two equations and 4 variables are given, put 2 of them any thing]
⇒ tanα + sinβ = m
m = 1 + \(\frac{1}{2}\) = \(\frac{3}{2}\)
⇒ cotα + cosecβ = n
n = 1 + 2 = 3
Put in find out
⇒ cosec2β (\(\frac{m}{n}\))2 + 4
⇒ (2)2 × \(\frac{1}{4}\) + 4 = 5
Now check options and satisfy.
From option A:
⇒ sec2α + cot2β = (\(\sqrt {2}\))2 + (\(\sqrt {3}\))2 = 5 satisfied
⇒ sec2α + cot2β is the correct answer.