Practicing Success
If 3 cot A = 4 tan A and A is an acute angle, then what will be the value of sec A ? |
$\frac{\sqrt{7}}{2}$ $\frac{\sqrt{21}}{2}$ $\frac{1}{\sqrt{3}}$ $\frac{1}{2}$ |
$\frac{\sqrt{7}}{2}$ |
3 cotA = 4 tanA cot²A = \(\frac{4}{3}\) cotA = \(\frac{2}{√3}\) { We know, cotθ = \(\frac{B}{P}\) } By using pythagoras theorem, P² + B² = H² 3 + 4 = H² H = √7 Now, secA = \(\frac{H}{B}\) = \(\frac{√7 }{2}\) |