If 3 cot A = 4 tan A and A is an acute angle, then what will be the v…

3 cotA = 4 tanA

cot²A = \(\frac{4}{3}\) 

cotA = \(\frac{2}{√3}\) 

{ We know, cotθ = \(\frac{B}{P}\) }

By using pythagoras theorem,

P² + B² = H²

3 + 4 = H²

H = √7

Now,

secA

= \(\frac{H}{B}\)

= \(\frac{√7 }{2}\)