CUET Preparation Today
In series LCR circuit, the rms potential drop across R. L and C are V, 2 V and 2 V volts respectively. The source voltage is: |
V 2 V 3 V 5 V |
V |
The correct answer is Option (1) → V The total source voltage ($V_{source}$) is - $V_{source}=\sqrt{{V_R}^2+(V_L-V_C)^2}$ $=\sqrt{V^2-(V-V)^2}$ $=V$ |
