In series LCR circuit, the rms potential drop across R. L and C are V, 2 V and 2 V volts respectively. The source voltage is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → V
The total source voltage ($V_{source}$) is -
$V_{source}=\sqrt{{V_R}^2+(V_L-V_C)^2}$
$=\sqrt{V^2-(V-V)^2}$
$=V$