Practicing Success
Practicing Success
CUET Preparation Today
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$\text{Apparaent depth of the vessel } d'= \frac{d}{2\mu} + \frac{d}{2\times 1.5\mu} = \frac{5d}{6\mu}$ $\text{It is given that } \frac{5d}{6\mu} = \frac{d}{2} $ $\Rightarrow \mu = \frac{5}{3}$ |
