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CUET
Physics
Ray Optics
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b
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d
$\text{Apparaent depth of the vessel } d'= \frac{d}{2\mu} + \frac{d}{2\times 1.5\mu} = \frac{5d}{6\mu}$
$\text{It is given that } \frac{5d}{6\mu} = \frac{d}{2} $
$\Rightarrow \mu = \frac{5}{3}$
