At certain places on earth, the angle of dip is 30°. If horizontal component of earth's magnetic field is H, then the total intensity of earth's magnetic field will be: |
$\frac{H}{2}$ $2H$ $\sqrt{\frac{3}{2}}H$ $\frac{2H}{\sqrt{3}}$ |
$\frac{2H}{\sqrt{3}}$ |
The correct answer is Option (4) → $\frac{2H}{\sqrt{3}}$ The total intensity of the earth Magnetic field, B is related to its horizontal component H and the angle of dip θ by following relationship - $B=\frac{H}{\cos θ}$ $θ=30°⇒\cos 30°=\frac{\sqrt{3}}{2}$ $B=\frac{H}{\frac{\sqrt{3}}{2}}=\frac{2H}{\sqrt{3}}$ |