If a + \(\frac{1}{a}\) + 2 = 0 Then find the value of (a + 2)41 + \(\frac{1}{(a + 2)^{41}}\) - 2. |
2 -2 0 1 |
0 |
If a + \(\frac{1}{a}\) + 2 = 0 it is possible only when a = -1 So put a = -1 in the required term = (a + 2)41 + \(\frac{1}{(a + 2)^{41}}\) - 2 = (-1 + 2)41 + \(\frac{1}{(-1 + 2)^{41}}\) - 2 = 0 |