Two trains, A and B start from station X and Y towards Y and X respectively.  After passing each other, they take 20 hours 50 minutes and 43 hours 12 minutes to reach Y and X respectively.  If train A is moving at 48km/h, then the speed of train B is?

\(\frac{100}{3}\) km/h

We have direct result

\(\frac{S_A}{S_B}\) = \(\sqrt {\frac{t_2}{t_1}}\)

Put and find:

\(\frac{48}{S_B}\) = \(\sqrt {\frac{216}{5} × \frac{6}{125}}\)

\(\frac{48}{S_B}\) = \(\frac{36}{25}\)

S_B = \(\frac{100}{3}\) km/h