Two trains, A and B start from station X and Y towards Y and X respectively. After passing each other, they take 20 hours 50 minutes and 43 hours 12 minutes to reach Y and X respectively. If train A is moving at 48km/h, then the speed of train B is?
Answer & explanation
Correct answer: option 3
We have direct result
\(\frac{S_A}{S_B}\) = \(\sqrt {\frac{t_2}{t_1}}\)
Put and find:
\(\frac{48}{S_B}\) = \(\sqrt {\frac{216}{5} × \frac{6}{125}}\)
\(\frac{48}{S_B}\) = \(\frac{36}{25}\)
SB = \(\frac{100}{3}\) km/h