The domain of the function $f(x)=\frac{\sin^{-1}(x-3)}{\sqrt{9-x^2}}$ is:
Answer & explanation
Correct answer: option 2
$-1≤x-3≤1$
$⇒2≤x≤4$
$9-x^2>0$
$x^2<9⇒-3<x<3$
so $⇒x∈[2, 3)$
The domain of the function $f(x)=\frac{\sin^{-1}(x-3)}{\sqrt{9-x^2}}$ is:
Correct answer: option 2
$-1≤x-3≤1$
$⇒2≤x≤4$
$9-x^2>0$
$x^2<9⇒-3<x<3$
so $⇒x∈[2, 3)$