CUET Preparation Today
CUET
-- Mathematics - Section B1
Relations and Functions
The domain of the function $f(x)=\frac{\sin^{-1}(x-3)}{\sqrt{9-x^2}}$ is:
[2, 3]
[2, 3)
[1, 2]
[1, 2)
$-1≤x-3≤1$
$⇒2≤x≤4$
$9-x^2>0$
$x^2<9⇒-3<x<3$
so $⇒x∈[2, 3)$
