Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

The domain of the function $f(x)=\frac{\sin^{-1}(x-3)}{\sqrt{9-x^2}}$ is:

Options:

[2, 3]

[2, 3)

[1, 2]

[1, 2)

Correct Answer:

[2, 3)

Explanation:

$-1≤x-3≤1$

$⇒2≤x≤4$

$9-x^2>0$

$x^2<9⇒-3<x<3$

so $⇒x∈[2, 3)$