The number of vectors of unit length perpendicular to vectors a ≡ (1, 1, 0) and b ≡ ( 0, 1, 1) is |
1 2 3 4 |
2 |
The vector of unit length perpendicular to the given vectors $=±\begin{pmatrix}\frac{a×b}{|a||b|}\end{pmatrix}$ Hence there are two such vectors. Hence (B) is the correct answer. |