The integrating factor of differential equation xdy/dx +2y=x2 log x is

$x.\frac{dy}{dx}+2y=x^2logx$

$\frac{dy}{dx}+\frac{2}{x}×y=xlogx⇒\frac{dy}{dx}+\frac{2y}{x}=xlogx$

$P=\frac{2}{x}$

$I.F.=e^{\int\frac{2}{x}dx}=e^{2logx}=x^2$

Option 4 is correct.