In a triangle PQR, XZ is parallel to QR, where X and Z are points on PQ and PR, respectively and PX = 3.5 cm, XQ = 7 cm and PZ = 2.5 cm, the length of ZR is?
Answer & explanation
Correct answer: option 3
\(\Delta \)PXZ ∼ \(\Delta \)PQR
\(\frac{PX}{XQ}\) = \(\frac{PZ}{ZR}\)
\(\frac{3.5}{7}\) = \(\frac{2.5}{ZR}\)
ZR = 5